已知函数fx=根号3(sin平方x-cos平方x)-2sinxcosx
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/13 22:05:42
派,负四分之派到四分之派,再问:可我不知道怎么写过程。
f(x)=-√3sin²x+sinxcosx=√3/2cos2x+1/2sin2x-1/2=sin(2x+π/3)+1/2T=2π/2=πf(π/6)=sin(π/3+π/3)+1/2=(1
f(x)=√3sin²x+sinxcosx=√3[(1-cos2x)/2]+1/2sin2x=1/2sin2x-√3/2cos2x+√3/2=sin(2x-π/3)+√3/2∵x∈[π/2,
fx=sin²wx+根号3倍的sinwxsin(wx+π/2)=(1-cos2wx)/2+√3sinwxcoswx=1/2-1/2cos2wx+√3/2sin2wx=sin(2wx-π/6)
当f(x)=2时,则√3sin(2x+π/4)+1=2.√3sin(2x+π/4)=1.sin(2x+π/4)=√3/3.2x+π/4=2kπ+arcsin(√3/3).2x=2kπ+arcsin(√
f(x)=1/2-1/2cos2x+√3/2sin2x-1/2=sin(2x-π/6)f(-π/12)=sin(-π/3)=-√3/2(2)-π/6
f(x)=2√3sinxcosx+2sin^2x-1=√3sin2x-cos2x=2sin(2x-π/6)最小正周期T=π,单调递增区间:2kπ-π/2
即代入可得,x=π/8+kπ(k=1,2,3.)
周期等于2派.g(x)=2sinx;基函数再问:有过程吗??再答:这可以看出来,还要过程吗,,,,周期等于2派/x前的数1===2派;;g(x)=2sint(x+pi/3+p1/3)=2sinx;si
F(X)=2√3sinx/2*cosx/2-(cos²x/2-sin²x/2)=√3sinx-cosx=2(√3/2sinx-1/2cosx)=2(sinxcosπ/6-sinπ/
F(X)=2√3sinx/2*cosx/2-(cos^2x/2-sin^2x/2).=√3sinx-cosx=2(√3/2sinx-1/2cosx)=2sin(x-π/6)当x-π/6=2kπ+π/2
答:f(x)=2sin(x-π/3)cosx+sinxcosx+√3(sinx)^2=sin(x-π/3+x)+sin(x-π/3-x)+sinxcosx+(√3/2)(1-cos2x)=sin(2x
答:y=f(x)=2√3sinxcosx-2sin²x=√3sin2x+cos2x-1=2*[(√3/2)sin2x+(1/2)cos2x]-1=2sin(2x+π/6)-1y=f(x)关于
第一题A.第二题B
(1)化简可得f(x)=(sin(x/2))^2+((√3)/2)sinx-0.5f'(x)=sin(x/2)cos(x/2)+((√3)/2)cosx=sinx+√3cosx=0√3cosx=-si
解答;f(x)=sin(2x+3分之π)∴sin(2x+π/3)=-3/5∵x∈(0,π/2)∴2x+π/3∈(π/3,4π/3)∵sin(2x+π/3)
解1当2kπ-π/2≤2x+π/3≤2kπ+π/2,k属于Z时,y是增函数即2kπ-5π/6≤2x≤2kπ+π/6,k属于Z时,y是增函数即kπ-5π/12≤x≤kπ+π/12,k属于Z时,y是增函数
f(x)=sin(x/2)cos(x/2)+√3*sin²(x/2)+√3/2=1/2*sinx+√3/2*(1-cosx)+√3/2=1/2*sinx-√3/2*cosx+√3=sin(x
fx=2根号3sinxcosx+1-2sin^2x=2sin(2x+π/6)周期为π