25x的平方-16y的平方
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(4x的平方加y的平方)的平方减16x的平方y的平方=(4x^2+y^2)^2-16x^2y^2=16x^4-8x^2y^2+y^4=(4x^2-y^2)^2=(2x+y)^2*(2x-y)^2
原式=(x²+y²+2xy)(x²+y²-2xy)/(x+y)²=(x+y)²(x-y)²/(x+y)²=(x-y)
25x²-16y²=(5x+4y)(5x-4y)
25x²+40x(y-x)+16(x-y)²25x²-40x(x-y)+16(x-y)²=[5x-4(x-y)]²=(x+4y)²
16(x+y)的平方-25(x-y)的平方=[4(x+y)]^2-[5(x-y)]^2=[4(x+y)+5(x-y)][4(x+y)-5(x-y)]=(9x-y)(9y-x)
25(x+y)的平方-9(x-y)的平方=[5(x+y)+3(x-y)][5(x+y)-3(x-y)]=(8x+2y)(2x+8y)=4(4x+y)(x+4y)
x²+y²=25x-y=7两边平方得:x²+y²-2xy=492xy=25-49=-24xy=-12(x+y)²=x²+y²+2x
原式=16(x+y)²+40(x+y)(x-y)+25(x-u)²=[4(x+y)+5(x-y)]²=(9x-y)²
(x平方+y平方)平方-y平方=x平方+6所以(x²+y²)²-(x²+y²)-6=0(x²+y²+2)(x²+y
((x-y)(x-y))/((x-y)(x+y))=(x-y)/(x+y).
16(x+y)的平方-25(x-y)的平方=[4(x+y)+5(x-y)][4(x+y)-5(x-y)]=(9x-y)(9y-x)
(x^2+y^2)^2-4x^2y^2=(x^2+y^2+2xy)(x^2+y^2-2xy)=(x+y)^2*(x-y)^2=(x^2-y^2)^2数学佰亊嗵为你解答,希望我的回答为您带来帮助!
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[5(x+y)]^2-[4(x-y)]^2=(5x+5y+4x-4y)(5x+5y-4x+4y)=(9x+y)(x+9y)
解题思路:(1)利用平方差公式分解因式;(2)把(b-a)转化为-(a-b)然后再提取公因式即可.解题过程:
25x的平方-16y的平方=(5x+4y)(5x-4y)
(x²+16y²)²-64x²y²=(x²+16y²)²-(8xy)²=(x²+16y²+
(x的平方+16y的平方)的平方-64x的平方y平方=(x的平方+16y的平方+8xy)(x的平方+16y的平方-8xy)=(x+4y)的平方(x-4y)的平方
X²+25=y²y^2-x^2=25(y+x)(y-x)=25y+x=土25y-x=土1y=土13x=土12
(x^2+4y^2)^2-16x^2y^2=(x+4y)-(4xy)=(x+4y+4xy)(x+4y-4xy)=(x+2y)(x-2y)请采纳回答