已知log8^9=a,log2^5=b,则lg3=?
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已知log8^9=a,log2^5=b,则lg3=?
先介绍换底公式:log(a)b=lgb/lga
证明:设log(a)b=t
则a^t=b,两边取以10为底的对数
lga^t=lgb
tlga=lgb
所以t=lgb/lga
所以log(a)b=lgb/lga
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log(8)9=a ==> lg9/lg8=a ==> 2lg3/(3lg2)=a ==> lg3=(3a/2)lg2
log(2)5=b ==> lg5/lg2=b ==> (lg10-lg2)/lg2=b ==> lg2=1/(b+1)
由此可得,lg3=3a/[2(b+1)]
证明:设log(a)b=t
则a^t=b,两边取以10为底的对数
lga^t=lgb
tlga=lgb
所以t=lgb/lga
所以log(a)b=lgb/lga
===========
log(8)9=a ==> lg9/lg8=a ==> 2lg3/(3lg2)=a ==> lg3=(3a/2)lg2
log(2)5=b ==> lg5/lg2=b ==> (lg10-lg2)/lg2=b ==> lg2=1/(b+1)
由此可得,lg3=3a/[2(b+1)]
已知log8^9=a,log2^5=b,则lg3=?
已知log8 9=a ,log2 5=b,则lg3等于什么(用a,b表示)
log8(9)=A log2(5)=B 那么lg3=()
已知3^a=5^b=A,若1/a+1/b=2,则A= 已知log8(9)=a,log2(5)=b,则lg3=
1.求值:log8^9/log2^3=?2.设lg2-a,lg3=b,求lg根号54.
已知log2^3=a.则log8^3= log8^9=
7log8^9=a log3^5=b 求lg2 lg3 lg5
log8(9)=a,log2(5)=b,则lg2)=?
log8(9)=a,log2(5)=b,则lg(3)=?
(log8 9/log2 3) =(lg9/lg8)/(lg3/lg2) ,这是为什么尼
(log8 9/log2 3)=?
已知lg2=a,lg3=b为什么log2 3=b/a?