解方程(2)(5x-4)/(2x-4)-1/2=(2x-5)/(3x+6)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/13 17:05:27
解方程(2)(5x-4)/(2x-4)-1/2=(2x-5)/(3x+6)
(5x-4)/[2(x-2)]-1/2=(2x-5)/[3(x+2)]
[5x-4-(x-2)]/[2(x-2)]=(2x-5)/[3(x+2)]
[4x-2]/[2(x-2)]=(2x-5)/[3(x+2)]
[2x-1]/(x-2)=(2x-5)/[3(x+2)]
二边同乘 3(x-2)(x+2)
3(x+2)(2x-1)=(2x-5)(x-2)
3(2x²+3x-2)=2x²-9x+10
6x²+9x-6=2x²-9x+10
4x²+18x-16=0
2x²+9x-8=0
x=[-9±√(9²-4*2*(-8))]/(2*2)
=(-9±√145)/4
[5x-4-(x-2)]/[2(x-2)]=(2x-5)/[3(x+2)]
[4x-2]/[2(x-2)]=(2x-5)/[3(x+2)]
[2x-1]/(x-2)=(2x-5)/[3(x+2)]
二边同乘 3(x-2)(x+2)
3(x+2)(2x-1)=(2x-5)(x-2)
3(2x²+3x-2)=2x²-9x+10
6x²+9x-6=2x²-9x+10
4x²+18x-16=0
2x²+9x-8=0
x=[-9±√(9²-4*2*(-8))]/(2*2)
=(-9±√145)/4
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