[√a+(b-√ab)/(√a+√b)]/[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]=
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[√a+(b-√ab)/(√a+√b)]/[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]=
楼主您好:
[√a+(b-√ab)/(√a+√b)]÷[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]
=[√a+(b-√ab)/(√a+√b)]÷[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]
=[a+√ab/(√a+√b)+(b-√ab)/(√a+√b)]÷[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]
=[a+b/(√a+√b)]÷[(√ab-1)(a+b)/√ab]
=√ab/(√ab-1)(√a+√b)
祝楼主学习进步
[√a+(b-√ab)/(√a+√b)]÷[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]
=[√a+(b-√ab)/(√a+√b)]÷[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]
=[a+√ab/(√a+√b)+(b-√ab)/(√a+√b)]÷[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]
=[a+b/(√a+√b)]÷[(√ab-1)(a+b)/√ab]
=√ab/(√ab-1)(√a+√b)
祝楼主学习进步
[√a+(b-√ab)/(√a+√b)]/[a/(√ab+b)+b/(√ab-a)-(a+b)/√ab]=
化简[√ab-ab/(a+√ab)]÷(√ab-a)/(a-b)
数学题(a√b-b√a)/√ab化简
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