a+b=7,ab=12,a^2-b^2=?
若a/b=2 则a*a-ab+b*b/a*a+b*b等于?
已知a+2b=0,求a*a+2ab-b*b/2a*a+ab+b*b
若a/b=2,求分式a*a+ab-b*b/a*a-2ab+2b*b
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
已知3a*a+ab-2b*b=0(a不等于0,b不等于0),求a/b-b/a-(a*a+b*b)/ab的值.
先化简,再求值;[(2a-b/a b)-(b/a-b)]÷{(a-2b/a b) [ab/(a-b)2]},其中b/a=
a^3+a^2b+ab^2+b^3 a+b=3 ab=-2
(12a^3b^2c^3-6a^2b+3ab)/3ab= [(a+b)^5-(a+b)^3]/(a+b)^3=
如果a+b=3,ab=-1,那么(a+b)2-a-b+ab=?
求证:A/(AB+B^2)-B/(AB+A^2)=1/B-1/A
若a+b=7求解[(a^2-b^2)/(a-b)]*a+b^2+ab
已知:|a|=2,|b|=4,a>b,ab