计算∫(-π/2到π/4)√[cosx-(cosx)^3]dx

计算∫(-π/2到π/4)√[cosx-(cosx)^3]dx ∫（π到0）根号下((cosx)^2-(cosx)^4)dx 计算定积分:∫cosx(1+sinx)dx,(区间0到π/2 ) 计算∫(-π/3),π/)][x/(1+cosx)]dx =∫(0,π/4)(cosx-sinx)dx+∫(π/4,π/2)(sinx-cosx)dx ∫【0到π/2】(sinx^10-cosx^10)dx/(5-sinx-cosx) 赶快∫【-π,π】[sinx/(x^2+cosx)]dx和∫【-π/4,-π/3】(sinx+cosx)dx求解 计算定积分 ∫(2sinx-3cosx)dx(上限17π/3 下限π/3) 求定积分∫x*√1+cosx dx 范围从0到2π ∫(0到2π）dx/(sinx^4+cosx^4) 计算该定积分 ∫ (π ,0) |cosx | dx 计算不定积分∫（cosX+e^2+3x）dx