证明:cos(a+b)=cosa*cosb-sina*sinb
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证明:cos(a+b)=cosa*cosb-sina*sinb
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2cos(a+b)=exp(i(a+b))+exp(-i(a+b))
=exp(ia)*exp(ib)+exp(-ia)*exp(-ib)
exp(ia)*exp(ib)
(cos(a)+isin(a))(cos(b)+isin(b))
=(cos(a)cos(b)-sin(a)sin(b))+i(sin(a)cos(b)+cos(a)sin(b))
同理
exp(-ia)*exp(-ib)
=(cos(-a)cos(-b)-sin(-a)sin(-b))+i(sin(-a)cos(-b)+cos(-a)sin(-b))
=(cos(a)cos(b)-sin(a)sin(b))-i(sin(a)cos(b)+cos(a)sin(b))
所以
2cos(a+b)=2(cos(a)cos(b)-sin(a)sin(b))
全式除以二即可.
=exp(ia)*exp(ib)+exp(-ia)*exp(-ib)
exp(ia)*exp(ib)
(cos(a)+isin(a))(cos(b)+isin(b))
=(cos(a)cos(b)-sin(a)sin(b))+i(sin(a)cos(b)+cos(a)sin(b))
同理
exp(-ia)*exp(-ib)
=(cos(-a)cos(-b)-sin(-a)sin(-b))+i(sin(-a)cos(-b)+cos(-a)sin(-b))
=(cos(a)cos(b)-sin(a)sin(b))-i(sin(a)cos(b)+cos(a)sin(b))
所以
2cos(a+b)=2(cos(a)cos(b)-sin(a)sin(b))
全式除以二即可.
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