先化简再求值[[(x2+2x+1)/(x+2)]÷[(x2-1)/(x-1)]-1/(x+2)其中x=√2-2

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/11 04:05:21

解
原式
=[(x+1)²/(x+2)]×[(x-1)/(x-1)(x+1)]-1/(x+2)
=[(x+1)²/(x+2)]×1/(x+1)-1/(x+2)
=(x+1)/(x+2)-1/(x+2)
=x/(x+2)
=(√2-2)/(√2-2+2)
=(√2-2)/(√2)
=1-√2

先化简，再求值：(x+2x2-2x-x-1x2-4x+4)÷x2-16x2+4x，其中x=2+3．先化简再求值[[(x2+2x+1)/(x+2)]÷[(x2-1)/(x-1)]-x/(x+2)其中x=√3-2 先化简再求值：(x-4/x2-1)÷(x2-3x-4/ x2+2x+1)+1/x-1.其中x=5 先化简再求值[[(x2+2x+1)/(x+2)]÷[(x2-1)/(x-1)]-1/(x+2)其中x=√2-2 化简求值x/x-1-x+3/x2-1 x x2+2x+1/x+3,其中x=√2+1 先化简再求值：(x2-x)/(x-1)*(x2-1)/(x2-2x+1)其中满足方程x2-3x+2=0 化简求值:X2/X2-1÷(1-2X/X-1-X+1)其中X满足X2+7X=0 化简求值,(3x/x-1-x/x+1)/x/x2-1,其中x=根号2-2 化简求值：[3x/(x-1)-2x/(x+1)*(x2-1)/x 其中x=根号5 -5 先化简再求值 x2-1分之x2-2x+1 +x+1分之1 其中,x=根号2-1 先化简,在求值:(X分之x2+4-4)除以x2+2x分之x2-4,其中x是方程x2+2x+1=10的解先化简,再求值:1-[(x)-1/1-x]2除以x2-x+1/x2-2x+1,其中x2-x+5=0