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计算 2xy[4x²y²-3y(xy+x²y)-xy²]

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计算 2xy[4x²y²-3y(xy+x²y)-xy²]
(2x-x²-3)(x³-x²-2)
(x²)³-2x³[x³-x²(4x+1)]
(-1/3xy)²·[xy(2x-y)-3x(xy-y²)]
计算 2xy[4x²y²-3y(xy+x²y)-xy²]
2xy [4x²y²-3y(xy+x²y)-xy²]
= 2xy [4x²y²-3xy²-3x²y²-xy²]
= 2xy [x²y²-4xy²]
= 2x³y³-8x²y³
(2x-x²-3)(x³-x²-2)
= (-x²+2x)(x³-x²) - 3(x³-x²) - 2(-x²+2x)+6
= -x³ (x-2)(x-1) - 3x³+3x²+2x²-4x+6
= -x³ (x²-3x+2) - 3x³+3x²+2x²-4x+6
= -x^5+3x^4-2x³ - 3x³+3x²+2x²-4x+6
= -x^5+3x^4-5+5x²-4x+6
(x²)³-2x³[x³-x²(4x+1)]
= x^6-2x³(x³-4x³-x²)
= x^6-2x³(-3x³-x²)
= x^6+ 6x^6+2x^5
= 7x^6+2x^5
(-1/3xy)²·[xy(2x-y)-3x(xy-y²)]
= (1/9x²y²)·(2x²y-xy²-3x²y+3xy²)
= (1/9x²y²)·(-1x²y+2xy²)
= -1/9x^4y³ +2/9x³y^4