x+3y+2z=2,3x+2y-4z=3,2x-y=7的解

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 解方程：{2x+3y+z=7,x+y+z=4,3x+y-z=-4 已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值 4x-3y-6z=0,x+2y-7z=0是一个方程组,那么x-y+z/x+y+z的值等于 2x+3y+4z=20;x+y+z=7 的解 x/2=y/3=z/5 x+3y-z/x-3y+z 已知4x-3y-6y=0,x+2y-7z=0.求x-y+z\x+y+z的值 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 已知2x=3y=4z求2x-y+z分之x+y+z的值 若x:y:z=2:3:4,求x+y+z/x-2y+3z的值 x：y：z=2：3：4 求 3x+2y-z/x+y+z 的值 x/3=y/4=z/5,求x+y+z/3x-2y+z的值,