3x - y + Z=4

x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 方程组｛4x-3y-3z=0,x-3y+z=0,(x.y.z不等于0),求x/z和y/z的值? 4x-3y-3z=0 x-3y+z=0 并且X Y Z不等于0 求x:z 和y:z的值 已知3X=4X,5Y=6Z求X+Y：Y+Z 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai 解方程：{2x+3y+z=7,x+y+z=4,3x+y-z=-4 解方程组x-y-3z=4 3x+y-z=6 -x+3y+z=8 已知 x-3y+z=0 3x-3y-4z=0,则x:y:z= 已知X-3Y+Z=0 3X-3Y-4Z=0.则X:Y:Z=? 已知x:y:z=3:4:5,3x+2y-4z=18.求：x+y+z.