.1 ..Y = 1 + --------------- ..1 ..1+ ----------- ..1 ..1+ -

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.1 .
.Y = 1 + --------------- .
.1 .
.1+ ----------- .
.1 .
.1+ ------ .
.x .
小弟在这里谢过了!

main()
{printf(".1.\n.Y = 1 + --------------- .\n.1.\n.1+ ----------- .\n.1.\n.1+ ------ .\n.x .\n");}

for(y=1;y for (y=1;y 解方程：3y^2-(2y+1)(y-1)=(y-5)(y+1) 解方程3y^2-(2y+1)(y-2)=(y-5)(y-1) matlab中y(:,y(:,1: 1- 6y+y² 求微分方程通解y"=1+y'＊y y·y''=1+y'^2求通解 y*y''+1=y'^(2),求通解. y'=(x-y+1)/(x+y-3)通解 arctan(y)=x+1, y=? 2y+8y-1=0