x+2y+(4y^2)/(x-2y)+(4x^2y)/(4y^2-x^2)

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/19 03:52:43

x+2y+[(4y^2)/(x-2y)]+[(4x^2y)/(4y^2-x^2)]
原式=(把前两个局部通分)[(x+2y)(x-2y)+4y^2]/(x-2y)+4x^2y/(2y+x)(2y-x)
=(前两个局部计算) x^2/(x-2y)-4x^2y/(x+2y)(x-2y):[注意最后一项的分母变成了：x-2y,所以前面的符号变成了：-]
=(在与最后的分式通分) [x^2(x+2y)-4x^2y]/(x+2y)(x-2y)
=(加减计算)(x^3-2x^2y)/(x+2y)(x-2y)
=x^2(x-2y)/(x+2y)x-2y)
=(约分化简) x^2/(x+2y)

x^2-y^2/x+y-4x(x-y)+y^2/2x-y, {(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y (2x-y)^2-4(x-y)(x+2y) (2x-y)²-4(x-y)(x+2y) 化简：（2x-y)²-4(x-y)(x+y) x+2y+4y^2/x-y+4x^y/4y^2-x^2 4x(y-x)-y^2因式分解 (x+3y-4)(2x-y) x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2 (2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y) 1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [（x+y)(x-y)-(x-y)^2+2y(x-y x+2y+4x^2y/4y^2+4y^2/x-2y