在△ABC和△ADE中,AB=AC,AD=AE,∠CAB=∠EAD.试说明CE=BD.

在△ABC和△ADE中,AB=AC,AD=AE,∠CAB=∠EAD.试说明CE=BD. 如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD.求证CE=BD 如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD=90°.求证CE=BD；CE⊥BD. 如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD=90°.求证:1：求证CE=BD；CE⊥BD. 如图,等腰三角形ABC和等腰三角形ADE中,AB=AC,AD=AE,∠CAB=∠EAD,试说明：△ACE≌ΔABD 如图,在△ABC和△ADE中,AC=AB,AE=AD,∠CAB=∠EAD=90° 三角形ABC和三角形ADE中,AB=AC,AD=AE.且角CAB=角EAD,求证CE=BD 如图(1),△ABC和△ADE中,已知AB=AC,AD=AE,且∠CAB=∠EAD 如图 △ABC和△ADE中,已知AB=AC,AD=AE且∠CAB=∠EAD,请说明BE=CD成立的理由 如图,AB=AC,AD=AE,BD=CE,BD与CE相较与点o,说明∠cab=∠ead=∠boc 如图,已知AB=AC,AD=AE,∠EAD=∠CAB,BD与CD相较于点O,求证说明：BD=CE． 如图,在△ABC和△ADE中,AB=AC,AD=AE,若BD=CE,求证∠ABD=∠ACE