MATLAB如何下做二元函数的曲线比如f(x,y)=x^2-y+1 f(x,y)=x^2-cosy+sinx

来源：学生作业帮编辑：神马作文网作业帮分类：综合作业时间：2024/11/10 11:47:05

x=linspace(-10,10,100);
>> y=linspace(-10,10,100);
>> z1=x.^2-y+1;
>> z2=x.^2-cos(y)+sin(x);
>> plot3(x,y,z1)
>> plot3(x,y,z2)

MATLAB如何下做二元函数的曲线比如f(x,y)=x^2-y+1 f(x,y)=x^2-cosy+sinx 求函数f(x,y)=sinx+cosy+cos(x-y),0≤x,y≤π/2的极值求多元函数极值f(x,y)=sinx+cosy+cos(x-y),0≤x,y≤π/2 二元函数f(x,y)=x+y/x-y,求f(y/x,x/y) 已知二元函数f(xy,x+y)=x^2+y^2,求f(x,y) matlab中一元函数：f=@(x)x^2+x^3+1.那么请问要表示成二元函数呢?（f(x,y)=1/x+1/y）已知函数f(x)满足f(0)=1,且对x,y∈R,恒有f(x+y)+f(x-y)=2f(x)*cosy.求f(x) 已知定义在R上的函数f(x)满足①:f(x+y)+f(x-y)=2f(x)cosy;②:f(0)=0,f(π/2)=1, 已知定义在R上的函数f(x)满足①:f(x+y)+f(x-y)=2f(x)cosy;②:f(0)=0,f(#/2)=1, 如何用matlab画f(x,y)函数图象? f(x,y)=x^2-y+1 定义在R上的函数f(x)满足①f(x+y)+f(x-y)=2f(x)cosy②f(0)=0,f(π/2)=1.求f(x) 求二元函数 f(x,y)=x2y2+xy,在条件x+2y=4下的极值

MATLAB如何下做二元函数的曲线 比如f(x,y)=x^2-y+1 f(x,y)=x^2-cosy+sinx