解方程:1/x+5+1/x+8=1/x+6+1/x+7
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解方程:1/x+5+1/x+8=1/x+6+1/x+7
要有过程
1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)
要有过程
1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)
1/(x+5)+1/(x+8)=1/(x+6)+1/(x+7)
等式左右分别通分:
(x+5+x+8)/(x^2+13x+40)=(x+6+x+7)/(x^2+13x+42)
所以(2x+13)/(x^2+13x+40)=(2x+13)/(x^2+13x+42)
所以(1):2x+13=0 即x=-13/2时:
等式明显成立
(2):2x+13≠0即x≠-13/2时:
x^2+13x+40=x^2+13x+42
此时即40=42,舍
所以综上:x=-13/2
等式左右分别通分:
(x+5+x+8)/(x^2+13x+40)=(x+6+x+7)/(x^2+13x+42)
所以(2x+13)/(x^2+13x+40)=(2x+13)/(x^2+13x+42)
所以(1):2x+13=0 即x=-13/2时:
等式明显成立
(2):2x+13≠0即x≠-13/2时:
x^2+13x+40=x^2+13x+42
此时即40=42,舍
所以综上:x=-13/2
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