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计算1)(2+1)(2^2 +1)(2^4 +1).(2^2n +1)2)100^2-99^2+98^2-97^2+96

来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/20 00:11:03
计算
1)(2+1)(2^2 +1)(2^4 +1).(2^2n +1)
2)100^2-99^2+98^2-97^2+96^2-95^2+.+2^2-1^2
3)(1-1/2^2)(1-1/3^2)(1-1/4^2).(1-1/9^2)(1-1/10^2)
4) (y-1/2)^2
5)(2x+3y)^2-(4x-9y)(4x+9y)+(2x-3y)^2
6) 1.2345^2+0.7655^2+2.469*0.7655
7) (x+2y)(x-y)-(x+y)^2
先化简后求值
1)(x+y)+(2x+y/1*2)+(3x+y/2*3)+.+(9x+y/8*9) x=2 ,y=9
计算1)(2+1)(2^2 +1)(2^4 +1).(2^2n +1)2)100^2-99^2+98^2-97^2+96
(1)原式=(2-1)*(2+1)*(2^2+1)*(2^4+1)*……*(2^n+1)
=(2^2-1*(2^2+1)*(2^4+1)*……*(2^n+1)
=(2^4-1)(2^4+1)*……*(2^n+1)
=(2^n+1)(2^n-1)
=2^2n-1
(2)100^2-99^2+98^2-97^2+96^2-95^2+.+2^2-1^2
=(100+99)(100-99)+(98+97)(98-97)+…………+(2+1)(2-1)
=100+99+98+97+…………+3+2+1=5050
1992^2-1993乘1991=
=1992×1992-(1992+1)(1992-1)
=1992×1992-(1992×1992-1×1)
=1
(3)(1-1/2^2)(1-1/3^2)(1-1/4^2).(1-1/9^2)(1-1/10^2)
=(1-1/2)(1+1/2)(1-1/3)(1+1/3)……(1-1/10)(1+1/10)
=(1/2)(3/2)(2/3)(4/3)……(9/10)(11/10)
中间约分约掉了
=(1/2)*(11/10)
=11/20
(4)(y-1/2)^2
=y^2-y+1/4
(5)(2x+3y)^2-(4x-9y)(4x+9y)+(2x-3y)^2
=4x^2+12xy+9y^2-16x^2+81y^2+4x^2-12xy+9y^2
=-8x^2+99y^2
(6)1.2345^2+0.7655^2+2.469*0.7655
=1.2345^2+2*1.2345*0.7655+0.7655^2
=(1.2345+0.7655)^2
=2^2
=4
(7)原式 = x^2-xy+2xy-2y^2-(x^2+2xy+y^2)
= -xy-3y^2
1)(x+y)+(2x+y/1*2)+(3x+y/2*3)+.+(9x+y/8*9)
=(x+2x+3x+...+9x)+(y+y/1*2+y/2*3+...+y/8*9)
=(1+9)*9x/2 +[y+(y-y/2)+(y/2-y/3)+(y/3-y/4)+...+(y/8-y/9)]
=45x+(8/9)y
代入 x=2 ,y=9
原式=98