已知x(2x 1)-(2x2-y)＝8 求x²+y²+2xy的值

已知x(2x 1)-(2x2-y)＝8 求x²+y²+2xy的值 已知x+y=8,xy=12,求x2+y2;(x-y)2的值 已知x(x-1)-(x2-y)=-3,求x2+y2-2xy的值 已知实数x,y满足(x2)+(y2)-xy+2x-y+1=0,求x,y的值 已知实数x、y满足X2+y2-xy+2x-y+1=0,试求x、y的值 已知x-y+1,X2+Y2=25 求（x+y）2和x2-xy+y2的值 已知|x-y+1|与x2+8x+16互为相反数，求x2+2xy+y2的值． 已知│x-y+1│与x2+8x+16互为相反数,求x2+2xy+y2的值. 已知x+y=-1,xy=-2,求代数式-5（x+y)+(x-y)+x(xy+y)的值 1.已知正数x,y满足x2-y2=2xy,求(x-y)/(x+y)的值 已知x+y=1 xy=-1/2 利用因式分解求x(x+y)(x-y)-x(x+y)²的值 正整数x,y满足x2-y2=2xy,求x-y/x+y的值