化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)]

化简cos(180°+x)*sin(x+360°)/[sin(-x-180°)*cos(-180°-x)] 化简[sin(180+x)-tan(-x)+tan(-360-x)]/[tan(x+180)+cos(-x)+cos(- 设f(x)=[2cos^3 x-sin^2 (360°-x)+2sin(90°+x)+1]/2+2cos^2 (180° sin(x+105°)cos(x-15°)-cos(x+105°)sin求化简 化简：{cos(180*0+x)sin(x+360*0)}/sin(-x-180*0)cos(-180*0-x) 化简sin(x-25°)sin(65°-x)+cos(x-25°)cos(65°-x)的结果为 f(x)=2(cosx)^3+sin(360°-x)^2-cos(180°-x)-3/2+2cos(180°+x)+co 化简cos²（-X）-【tan（360°+X）】/【sin（-X）】 求值：sin(10°+x)cos(50°-x)+sin(50°-x)cos(10°+x) 【三角恒等变换】cos(33°-x)sin(63°-x)-cos(x+57°)sin(27°+x) 化简：[2cos³x－sin²(360°－x)＋2sin(90°+x)+1]÷[2+2cos&sup 化简f(x)=2cos^3 x+sin^2 (360-x)-cos(180-x)-3 / 2+2cos^2(180+x)