神马作文网用换元法解分式方程x^2-2x+7/x^2-2x=8
来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/19 18:50:52
用换元法解分式方程x^2-2x+7/x^2-2x=8
jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
答
x^2-2x+7/x^2-2x=8
设y=x^2-2x
则
y+7/y=8
y^2-8y+7=0
(y-7)(y-1)=0
y=7或y=1
x^2-2x=7
x^2-2x-7=0
求根公式得
x=1±2√2
x^2-2x=1
x^2-2x-1=0
求根公式得
x=1±√2
综上
方程解
为x=1±2√2或x=1±√2
x^2-2x+7/x^2-2x=8
设y=x^2-2x
则
y+7/y=8
y^2-8y+7=0
(y-7)(y-1)=0
y=7或y=1
x^2-2x=7
x^2-2x-7=0
求根公式得
x=1±2√2
x^2-2x=1
x^2-2x-1=0
求根公式得
x=1±√2
综上
方程解
为x=1±2√2或x=1±√2
分式方程.x/(x-2)+(x-9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)
用换元法解分式方程x^2-2x+7/x^2-2x=8
用换元法解分式方程2(x²+1)/x+6x/x²+2=7
x-1\x-2+x-6\x-7=x-2\x-3+x-5\x-6 分式方程
解分式方程,7/(x^2+x)+3/(x^2-x)=6/(x^2-1)
解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得
x/(x-2)+(x+1)/(x-6)=2x/(x-3) 解分式方程
用换元法解分式方程x2+x+1=2x
解分式方程：2x+1x
解分式方程：2x
解分式方程[（x＋2)／(x＋1)]＋[(x＋8)／(x＋7)]=[(x＋6)]／[(x＋3)]＋[(x＋4)}／[(x
用换元法解分式方程3x^2+3x=（x^2+x分之2）+1