解方程:1/(x2-5x+6)-1/( x2-4x+3)+1/( x2-3x+2)=1/(x-1)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/12 02:49:56
解方程:1/(x2-5x+6)-1/( x2-4x+3)+1/( x2-3x+2)=1/(x-1)
利用
1/(m2+m)=1/[m*(m+1)]=1/m-1/(m+1)解题规律做
利用
1/(m2+m)=1/[m*(m+1)]=1/m-1/(m+1)解题规律做
1/(x²-5x+6)-1/( x²-4x+3)+1/( x²-3x+2)=1/(x-1)
1/[(x-2)(x-3)]-1/[(x-1)(x-3)]+1/[(x-1)(x-2)]=1/(x-1)
1/(x-3)-1/(x-2)-1/[(x-1)(x-3)]+1/(x-2)-1/(x-1)=1/(x-1)
1/(x-3)-1/(x-1)-1/[(x-1)(x-3)]=1/(x-1)
2/[(x-3)(X-1)-1/[(x-1)(x-3)]=1/(x-1)
1/(x-3)(x-1)=1/(x-1)
x²-4x+3=x-1
x²-5x+4=0
(x-1)(x-4)=0
x=1(不合题意,舍去)
∴x=4
1/[(x-2)(x-3)]-1/[(x-1)(x-3)]+1/[(x-1)(x-2)]=1/(x-1)
1/(x-3)-1/(x-2)-1/[(x-1)(x-3)]+1/(x-2)-1/(x-1)=1/(x-1)
1/(x-3)-1/(x-1)-1/[(x-1)(x-3)]=1/(x-1)
2/[(x-3)(X-1)-1/[(x-1)(x-3)]=1/(x-1)
1/(x-3)(x-1)=1/(x-1)
x²-4x+3=x-1
x²-5x+4=0
(x-1)(x-4)=0
x=1(不合题意,舍去)
∴x=4
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