As in right figure,in a quadrilater
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As in right figure,in a quadrilateral ABCD,we have its diagonal AC bisects∠DAB,and AB=21,AD=9,BC=DC=10,then the distance from point C to line AB is______,and the length of AC is______. (英汉词典:quadrilateral 四边形;bisect 平分)
过C作CE⊥AD,CF⊥AB,
∴△CED≌△CFB,
∴DE=FB,
∴9+DE=21-BF,
∴BF=6,
根据勾股定理,可知CF=CE=8,即点C到AB的距离为8.
∴AC=
AF2+CF2=
152+82=17.
故答案为:8,17.
∴△CED≌△CFB,
∴DE=FB,
∴9+DE=21-BF,
∴BF=6,
根据勾股定理,可知CF=CE=8,即点C到AB的距离为8.
∴AC=
AF2+CF2=
152+82=17.
故答案为:8,17.
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