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求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π

来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/07 10:52:20
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)的值
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π
sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)
=sin(4π+π/6)+cos(2π-π/3)+tan(-6π-π/4)+sin(-2π-π/3)*cos(-2π-π/6)-sin(-2π+π-π/6)*cos(-2π+π/3)
=sin(π/6)+cos(-π/3)+tan(-π/4)+sin(-π/3)*cos(-π/6)-sin(-π/6)*cos(π/3)
=1/2+1/2+(-1)+(-√3/2)*(√3/2)-(-1/2)*(1/2)
= - 1/2