a^2-b^2/2÷(a-2ab-b^2/a)
a+b/2ab
2AB/A+B
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
化简 (a²+b²/a²-b²-a-b/a+b)÷2ab/(a-b)(a+b)&
(a-b)(a^2+ab+b) 化简
若a/b=2 则a*a-ab+b*b/a*a+b*b等于?
先化简,再求值;[(2a-b/a b)-(b/a-b)]÷{(a-2b/a b) [ab/(a-b)2]},其中b/a=
因式分解a^+b^+2a^b+2ab^+a^+b^+3ab+a+b
(a+b/a-b)²×2a-2b/3a+3b÷ab/a²-b²
计算 (a²-2ab+b²-a+b)÷(a-b) (a+b)²÷(a-b)
3ab+3b²/b(a²+2ab+b²) ×a²-b²/a-b ÷b/
(a^2-b^2)/(a^2b+ab^2)÷[2-(a^2+b^2/ab)]