对数函数怎么化简[log2(10)+log5(10)]/[log2(10)*log5(10)]
对数函数怎么化简[log2(10)+log5(10)]/[log2(10)*log5(10)]
(1/log2 10) + (1/log5 10) =lg2 + lg5
比较a=log2为底4的对数 b=log5为底10的对数 c=log7为底14的对数的
log4^25-2log4^10+log2^9×log3^根号5×log5^2
log2/log5等于多少
2log5^10+log5^0.25=?
计算log的题目2log5 10+2log5 0.5+log2 1+3log3 3log后为系数,特隔空格区分,
(log2)和(log3)变成(log5)
log2(5)*log5(8)化简
运用对数换底公式化简log2(3)*log3(4)*log4(5)*log5(2),
2log5^10+log5^0.25=? 顺便解释怎样化简, 谢谢
2乘log5的底数以10的对数加log5的底数以0.25的对数等于多少