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24[1/8(3x-1+x²)-2/3(x³-2x²+3)-x}

来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/11 07:32:08
24[1/8(3x-1+x²)-2/3(x³-2x²+3)-x}
24[1/8(3x-1+x²)-2/3(x³-2x²+3)-x}
24[1/8(3x-1+x²)-2/3(x³-2x²+3)-x]
=24*1/8(3x-1+x²)-24*2/3(x³-2x²+3)-24*x
=3(3x-1+x²)-16(x³-2x²+3)-24x
=9x-3+3x²-16x³+32x²-48-24x
=-16x³+3x²+32x²+9x-24x-3-48
=-16x³+35x²15x-51
（2x²-2x+3)(-x³+x-1) (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 6x+(2x²-3x)-(x²-1) (1-x/3-x)²/(3-2x-x²/9-x²)³*(x²/x 1.(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x 4x²-1/3x²-x·9x³-x/2x^4-x³计算 急 x²+3x+9/(x²-27)+6x/(9x-x²)-(x-1)/(6+2x) x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) (x+1)/(x²+3x+2)+(x²-2x)/(x²-4) x(x²-1)+2x²（x+1)-3x（2x-5)计算 ①2(x+3)(x-3)=x²+(x-1)(x+1)+2x