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计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]

来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/14 06:56:22
计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
计算：[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
[(x-1)/(x^2-x-2)]^2/(x^2-2x+1)/(2-x)/[1/(x^2+x)^2]
=(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)/{1/[x²(x+1)²]}
=(x-1)²/[(x-2)(x+1)]²/(x-1)²/(2-x)*x²*(x+1)²
=-x²/(x-2)
分式混合计算(x+1/x^2-x - x/x^2-2x+1)*x x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) 计算 x(x+3)-(x-1)(x-2） 如何计算 (x+1)(x+2)(x+3)(x+4) 计算：（x+1)(x-2)(x-3)(x-6) 计算(X-1)(X-2)(X-3)(X-4) 计算x/(x^2-1) + (x^-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1) {2X+1}+{X} x^2-|x|+1 ｜x-1｜+｜x-2｜ x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4