x²+4x+3=x²+4x+4-4+3=x²+4x+4-1=(x+2)²-1=(
x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x
已知f(x)={x²-3x+4(x>0),{1-x(x
先化简再求值:(x+2/x²-2x - x-1/x²-4x+4)÷ x-4/x,其中x=3/2
3X+(X+2)+(X+1)*(X-1)=4*(X²+8)
解方程:x(6-x)-2x(x+1)-(x^3-3x^4)/x²=4
4x²-{-3x²-[5x-x²-(2x²-x)]+4x},其中x=½
解方程(x²-x+4)x-(x-1)(x²+2)=x+7
(x+2)/x(x-2)-(x-1)/x²-4x+4=几,
2X²-X=6,4X²-3X-1=X-2,3X(X-3)=2(X-1)(X+1),
2f(x)+x^2f(1/x)=(3x³-x²+4x+3)/(x+1) 2x²f(1/x)
解方程 (3x+1)(3x-1)=(x+2)(9x-4) 2(x-3)(x-2)-(x+3)²=(x-1)(x
解方程:1.x/x+1-1=3/(x+1)(x-2) 2.3/x+2+1/x=4/x²+2x 3.2/3+x/