cos^3(2x)sin(2x)dx求解

cos^3(2x)sin(2x)dx求解 微积分求解：∫sin^3 (x) cos^2 (x) dx 求解 ∫sin(6x)^3*cos(6x)^8 dx=? 范围[pi/2,0] ∫sin(x) cos^2(x)dx 求不定积分 ：| ( sin^2 x / cos^3x ) dx 求积分：∫sin^2 (x) /cos^3 (x) dx ∫ [cos^3(x)]/[sin^2 (x)]dx ∫sin^3(x)cos^2(x)dx= ∫(cos^3x/sin^2x)dx 求解∫cos^2(1-2x)dx,∫(sin ax cos ax) 用第二积分换元法 ∫dx/[sin^2(x/2)cos^2(x/2)] ∫sin^2(x)cos^2(x)dx