(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
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(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)
=(cosπ/12 - sinπ/12)(sinπ/12 + cosπ/12)
=cos²(π/12) - sin²(π/12)
=cos(π/6)
=(根号3)/2
再问: (sin5π/12-sinπ/12)(cos5π/12+cosπ/12)怎么会变成(cosπ/12 - sinπ/12)(sinπ/12 + cosπ/12)
再答: 公式:sin(π/2 - α)=cosα,cos(π/2 - α)=sinα
=(cosπ/12 - sinπ/12)(sinπ/12 + cosπ/12)
=cos²(π/12) - sin²(π/12)
=cos(π/6)
=(根号3)/2
再问: (sin5π/12-sinπ/12)(cos5π/12+cosπ/12)怎么会变成(cosπ/12 - sinπ/12)(sinπ/12 + cosπ/12)
再答: 公式:sin(π/2 - α)=cosα,cos(π/2 - α)=sinα
(sin5π/12-sinπ/12)(cos5π/12+cosπ/12)=?
(sin5π/12+cos5π/12)(sinπ/12-cosπ/12)
sin5/12π×cos5/12π怎么算?
cos5π/12=sinπ/12
cos5/12πcosπ/12+cosπ/12sinπ/6=?
(sin5π12−sinπ12)(sin5π12+sinπ12)
数学极限的运算lim α→π/2 (sinα-sin5α)/(cosα+cos5α)
不查表求值:cos5π/12·sinπ/12=
sin5/12π*cosπ/12 怎么算
为什么cos5π/12等于sinπ/12
已知角α终边上一点坐标为(sin5π/6,cos5π/6)求sinα和cosα的值
帮我解,证明恒等式(cos平方5π/12)+(cos平方π/12)+(cos5π/12)(cosπ/12)=5/4