证明x^2(d^2y/dx^2)+a_1x(dy/dx)+a_2y=0 ,令x=e^t,方程可化成d^2y/dt^2+(
证明x^2(d^2y/dx^2)+a_1x(dy/dx)+a_2y=0 ,令x=e^t,方程可化成d^2y/dt^2+(
已知 x=e^t ,dy/dx=dy/xdt .分析变换具体步骤 d^2y/dx^2=(d^2y/dt^2-dy/dt)
参数方程的二阶导数中d^2y/dx^2=(d/dx)(dy/dx)=(d/dt)(1/dx/dt)(dy/dx),是一个
如图.令x=e^t,为什么y''x^2=(d^2y)/(dt^2)-dy/dt?
参数方程求导这个问题怎么解释 d^2y/dx^2=[d/dt(dy/dx)]/dx/dt
d^2y /dx^2 - 24 =0 dy/dx -2y = e^-x
令x=cost,变换方程d^2y/dx^2-x/(1-x^2)*dy/dx+y/(1-x^2)=0
已知参数方程x=e^(2t)-1,y=2e^t,求dy/dx,d^2y/dx^2
设函数y=y(x)由x=1-e^t和y=t+e^-t确定,求dy/dx和d^2y/dx^2
y= ∫[0,x](t-1)^3(t-2)dt,dy/dx(x=0)
高数中若dy/dt=(dy/dx)*cost 那么d^2 y/dx^2 怎么求
d^2y/dx^2=(dy/dx)'×(dy/dx),另外请解释下dx,dy的含义,dx和dy是指x=...和y=...