请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/23 22:30:53

请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2)=?csc(x+π/2)=?
还有sin(x+π)=?cos(x+π)=?tan(x+π)=?cot(x+π)=?sec(x+π)=?csc(x+π)=?

sin(x+π/2)=cos x
cos(x+π/2)=-sinx
tan(x+π/2)=sin(x+π/2)÷cos(x+π/2)=cos x÷(-sinx) = -cotx
cot(x+π/2)=1÷tan(x+π/2)=1÷（-cotx）= - tan x
sec(x+π/2)=1÷cos(x+π/2)=1÷(-sinx)=(-1/sinx)
csc(x+π/2)=1÷sin(x+π/2)=1÷(cos x)=1/cosx
sin(x+π)=-sinx
cos(x+π)=-cosx
tan(x+π)=sin(x+π)÷cos(x+π)=（-sinx）÷（-cosx）=tan x
cot(x+π)=1÷tan(x+π)=1÷tan x = cot x
sec(x+π)=1÷cos(x+π)=1÷(-cosx)=(-1/cos x)
csc(x+π)=1÷sin(x+π)=1÷(-sinx)=(-1/sin x)

请问sin(x+π/2)=?cos(x+π/2)=?tan(x+π/2)=?cot(x+π/2)=?sec(x+π/2) 证明(tan^2x-cot^2x)/(sin^2x-cos^2x)=sec^2x+csc^2x 证明(tan^2x-cot^2x)/(sin^2x+cos^2x)=sec^2x+csc^2x 已知函数f(x)=sin^2x+csc^2x+cos^2x+sec^2x+tan^2x+7cot^2x,x∈(0,π/4 求sin^2(x)+tan^2(x)+csc^2(x)+sec^2(x)+cos^2(x)+cot^2(x)=31里,x f(x)=|sin x+cos x+tan x+cot x+sec x+csc x|最小值 f(a)=[sin(π-x)cos(2π-x)tan(-x+3π/2)]/cot(-x -π)sin(-π--x) 化简设函数f(x)=[cot(-x-π)sin(2π+x)]/[cos(-x)tan(3π-x)].(1)若f(α)=（根3 证明sec x+tanx=tan(π/4 +x/2) 化简cos(π/2-x)cos(π/2+x)cot(π-x)/sin(3π/2+x)cos(3π+x)tan(π+x) 已知(x)=[sin(π-x)cos(2π-x)tan(-x+π)]/[cos(-π/2+x)] f(x)=|sin x+cos x+tan x+cot x+sec x+csc x|最小值答对马上采纳,