作业帮 > 数学 > 作业

[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11

来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/17 07:15:11
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11,y=1/12,化简再求值.
[(y*y*y-y)/(xy+1)*(xy+1)-(x+y)*(x+y)]/[(x+y)*y/(x+1)]其中x=-11
原式=[y(y+1)(y-1)/(xy+1+x+y)(xy+1-x-y)]*[(x+1)/u(x+y)]
=[y(y+1)(y-1)/(x+1)(y+1)(x-1)(y-1)]*[(x+1)/y(x+y)]
=[y/(x+1)(x-1)]*[(x+1)/y(x+y)]
=1/(x-1)(x+y)
=1/131
xy-1+x-y x²+xy/(x-4y)(x+y),其中x=4,y=-1 （x+y)*（x+1)-(xy+y*y)因式分解为多少 先化简,再求值(x-y/x+y)^2÷(y-x/x^2+2xy+y^2)^2*1/x+y,其中x=-4,y=1 （x+2y-3xy)-(-2x-y+xy),其中x+y=1/2,xy=-1/2 (x+y-2xy)(x+y-2)+(1-xy)² 1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y) x>1,y>0,且满足xy=x^y,x/y=x^3y,求x+y x+y)(x-y)+(x-y)^2-(6x^2y-2xy^2)/2y,其中x=-2,y=1/3 xy+x+y+1因式分解 1-x-y+xy 因式分解 因式分解xy-x-y+1