求y=sin(2x-π/3) +1 X∈(-π/3,2π/3)的值域,谢谢

求函数的值域y=sin(2x+π/3),x∈(-π/6,π) 求y=3sin(2x+π/3)-1的值域(x∈[-π/4,π/3] 求函数y=sin(π/6-3x),x∈(π/6,π/2]的值域 求详解 求函数y=3-2sin(x+π/6),x∈[0,2π]的值域 求函数y=3sin^2x-4cosx+1,x属于[π/3,2π/3]的值域 求y=sin方x+2sinx+3的值域要过程谢谢了 Y=log0.2[1-2sin(2x+π/3)],求定义域,值域.周期, 求下列函数的值域 (1)y=3sin(2x+π/2)-1 (x∈[-π/4,π/3]) (2)y=(cosx)^2-3c 求函数的值域y=sin²x+cosx+1,x∈[-π/3,π/3] 求函数y=2sin(2x+π/3),x属于(-π/6,π/6)的值域 0≤x≤π/2,求函数y=sin(2x+π/3)的值域 函数Y=1+2sin(3x+π/2)在X∈[0,π/3]的值域是