(1+y-x^2+x^2y-2xy)(1+y-x^2+x^2y+2xy)分解因式
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/09/29 15:24:34
(1+y-x^2+x^2y-2xy)(1+y-x^2+x^2y+2xy)分解因式
(1+y-x^2+x^2y-2xy)(1+y-x^2+x^2y+2xy)
最后要化成
(x-1)(xy-x-1-y)(x+1)(xy-x+1+y)
说出道理
2l
好象复杂了些..............
..............
其实应该很简单...........
1l
什么乱器八糟的..........不就是想挣分嘛........
好好答..........
(1+y-x^2+x^2y-2xy)(1+y-x^2+x^2y+2xy)
最后要化成
(x-1)(xy-x-1-y)(x+1)(xy-x+1+y)
说出道理
2l
好象复杂了些..............
..............
其实应该很简单...........
1l
什么乱器八糟的..........不就是想挣分嘛........
好好答..........
(1+y-x^2+x^2y-2xy)(1+y-x^2+x^2y+2xy)分解因式
=[(1-x^2)+(x^2y-2xy+y)][(1-x^2)+(x^2y+2xy+y)]
=[(1-x^2)+y(x^2-2x+1)][(1-x^2)+y(x^2+2x+1)]
=[(1+x)(1-x)+y(x-1)^2][(1+x)(1-x)+y(x+1)^2]
=(x-1)[-(x+1)+y(x-1)](x+1)[1-x+y(x+1)]
=(x-1)(xy-x-y-1)(x+1)(xy-x+y+1)
=[(1-x^2)+(x^2y-2xy+y)][(1-x^2)+(x^2y+2xy+y)]
=[(1-x^2)+y(x^2-2x+1)][(1-x^2)+y(x^2+2x+1)]
=[(1+x)(1-x)+y(x-1)^2][(1+x)(1-x)+y(x+1)^2]
=(x-1)[-(x+1)+y(x-1)](x+1)[1-x+y(x+1)]
=(x-1)(xy-x-y-1)(x+1)(xy-x+y+1)
分解因式:(X+Y)*(X+Y+2XY)+(XY+1)*(XY-1)
x^2-xy+y^2 分解因式
求解一道数学题;(xy-1)^2+(x+y-2)(x+y-2xy) 分解因式
分解因式(xy-1)^2+(x+y-2)(x+y-2xy)
分解因式:(X+Y-2XY)*(X+Y-2)+(1-XY)∧2
分解因式:(xy-1)的平方+(x+y-2)(x+y-2xy).
分解因式:(1-x^2)(1-y^2)+4xy
x²+2xy+y²-1 分解因式
【分解因式】 x²-xy+4分之1y² x²y-2xy²+y³ a(x
分解因式2x²y-x³-xy²
分解因式:xy(xy+1)+(xy+3)−2(x+y+12)−(x+y−1)
(x^2+2xy+y^2)+(-2x+2y)+1分解因式