x-5=y+2 (x-5)(y+2)=xy 怎么算

整数x,y满足方程2xy+x+y=83,则x+y怎么算 已知x+y=-1,xy=-2,求代数式-5（x+y)+(x-y)+x(xy+y)的值 [-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y- 若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y* 若x+y-5xy=0,求(2x-3xy+2y)/(x+2xy+y)的值 已知xy=2(x+y),求(5x-xy+5y)/(3xy-x-y)的值 已知x+y分之xy=2,那么3x-5xy+3y分之3xy-x-y= 已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y= 已知xy/x+y=3,求代数式2x-5xy+2y/x-3xy+y 已知xy/x+y=2,求代数式3x-5xy+3y/-x+2xy-y的值 已知x-y=2xy,求代数式3x-5xy-3y/x+xy-y的值 已知X+Y=2XY,求4X-5XY+4Y 除以X+XY+Y 的值