2除以sin2θ+cos(π+θ)除以cos(π除以2-θ)化简
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2除以sin2θ+cos(π+θ)除以cos(π除以2-θ)化简
2除以sin2θ+cos(π+θ)除以cos(π除以2-θ)
=2/sin2θ+cos(π+θ)/cos(π/2-θ)
=2/sin2θ-cosθ/cos(π/2-θ)
=2/sin2θ-cosθ/sinθ
=2/sin2θ-2cosθcosθ/2sinθcosθ
=2/sin2θ-2cos^2θ/sin2θ
=(2-2cos^2θ)/sin2θ
=2(1-cos^2θ)/sin2θ
=2sin^2θ/sin2θ
=2sin^2θ/2sinθcosθ
=sinθ/cosθ
=tanθ
=2/sin2θ+cos(π+θ)/cos(π/2-θ)
=2/sin2θ-cosθ/cos(π/2-θ)
=2/sin2θ-cosθ/sinθ
=2/sin2θ-2cosθcosθ/2sinθcosθ
=2/sin2θ-2cos^2θ/sin2θ
=(2-2cos^2θ)/sin2θ
=2(1-cos^2θ)/sin2θ
=2sin^2θ/sin2θ
=2sin^2θ/2sinθcosθ
=sinθ/cosθ
=tanθ
求证(1-sinθcosθ)除以(cos^2θ-sin^2θ)=(cos^2θ-sin^2θ)除以(1+2sinθcos
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