化简求值:sin(π4−3x
求值:sin(π/12)+cos(π/12)
求值:sin[1/2arctan(-4/3)]
求值sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-
求值:sin(π/4)cos(19π/6)tan(21π/4)急!
求值,谢谢高手! 已知 Sin(α+3/4π)= 5/13
不查表求值:cos5π/12·sinπ/12=
求值:⑴sin(-19π/3)*cos(19π/6)
化简求值:sin(π/4-3x)*cos(π/3-3x)-cos(π/6+3x)*sin(π/4+3x)
求值并比较sin(-54π/7)与sin(-63π/8)的大小
sin^a+cos^(π/6+a)+1/2sin(2a+π/6)求值
已知tanα=2,求值√2sin(α+π/4)/1+sinα-2cos^2α/2