log27^4*log8^9+2log4^9-4 要崩溃了- -表示不认真听课的下场啊..
关于log的计算log8(9)* log27 (32)log4 (3) *log9(2)- log 1/2(四倍根号下3
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8(
(log8^27)/(log4^9)的值
化简log3(4)*log4(5)*log5(8)*log8(9)的结果是?
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
已知4^a=3 代数式log8(9)-2^(log4(3))
log4 8-log8 4=?
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
(log3^2 + log9^4)×(log4^3 + log8^3)
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?
(log2 3+log4 27)(log3 4+log27 16)