if(ch[0]==9)("Theresultof%d!is:\n",n);

char a=0,ch; while((ch=getchar())!='\n') { if(a%2!=0&&(ch>=' if ((n!=0)&&(n #include main() {char ch; ch='A'+'5'-'3'; printf("%d,%c\n",c if(a!=0) printf("%d\n",x); else printf("%d\n", main() { char ch; ch='H'-'A'+'0'; printf("%c\n",ch); } #include int gcd(int m,int n) { if(m%n==0) printf("%d\n",n); c++ 用二分法计算x^n（n>=0）的值（if n is even,xn=xp* xp; if n is odd,xn if ((n & -n) == n) void p(int n) { if (n>1 &&n%2==1) p(n-1); printf(“%2d”,n); i c语言,if(year%4==0&&year%100!=0) printf("%d is a leap year.\n" C语言中n = ch - main(){int m=7,n=5,i=1;do{if(i%m==0);if(i%n==0){printf("%d\n