lim(x->0)((1/x)-ln(1+x)/x^2) 答案是1/2,
lim(x->0)ln(1+2x)/e^x-1
lim(x→0)ln(1-2x)/x
lim(x趋向0)ln(1+sin x)/x^2
lim(x趋于0)[ln(1+2x)]/x
lim x趋近于0 (arctanx-x)/ln(1+2x^3)答案是多少?
lim(x趋近于0)[1/ln(x+根号1+x^2)-1/ln(1+x)]
lim(x→0)(cosx)^(1/ln(1+x^2))
lim e^2x-1/ln(1-X) 0
lim(x→0)ln(x^2+1)等于
lim(x→0)(ln(1+x^2)/(sec-cosx))
怎么计算lim(x->0+)x^(1/2)*ln(sinx)?
lim[ln(1+x^2)]/(secx-cosx) x->0