△ABC中,AB=AC、AD是高,求证BD=CD,∠BAD∠DAC
2第7题△ABC中,AB=AC,AD是高。求证(1)BD=CD(2)∠BAD=∠CAD
如图△ABC中,AB=AC,AD是高.求证:(1)BD=CD;(2))∠BAD=∠CAD 最好用HL证明的
如图,△ABC中,AB=AC,AD是高.求证:(1)BD=CD(2)∠BAD=∠CAD
如图,在三角形ABC中,AB=AC,AD是高.求证:(1)BD=CD (2)∠BAD=∠CAD
△ABC中,∠ACB=2∠B,AD平分∠A,∠BAD=∠DAC,求证AB=AC+CD
已知:△ABC中,∠C=2∠B,AD平分∠BAC,∠BAD=∠DAC,求证:AB=AC+CD
已知三角形ABC中,AD是高,AB+CD=AC+BD.求证:AB+BC
已知:如图,在△ABC中,∠BAD=30°,BD=CD,AD⊥AC,求证:AC=1/2AB
三角形ABC中,AB=AC,AD是高.求证:(1)BD=CD;(2)角BAD=角CAD.
如图在角ABC中,AB=AC.AD是高求证1.BD=CD 2.角BAD=角cad
如图,在△ABC中,AB=AC,AD是高,求证(1)BD=CD,(2)
如图所示,在△ABC中,AD平分∠BAC,CD⊥AC,AD=BD.求证:AB=2AC.