3y-30=x+10 x-10=y+10 化简
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
解方程组:(0.2x+0.1y)/2- (4x-y)/10=(x-y)/5+ (3x+0.5y)/30 (3x+2y-1
已知/x/+x+y=10,/y/+x-y=12.求x+y的值
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
X+Y=7(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y)
已知实数x,y满足|x|+x+y=10、x+|y|-y=12,则x+y的值?
用加减法解方程组:{(x+y)/6+(x-y)/10=3 (x+y)/6+(y-x)/10=-1
解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1
解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)
{ x-y/7-x+y/10=1/2 {2(x-y)+5(x+y)=3
已知x-y-3绝对值+(2x+2y+10)的平方=0,则(x+y)(x-Y)=
已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y