x^2+4xy+4y^2-2x-4y-3 过程谢谢
因式分解 求过程 x-xy+3y-3x 2x+xy-y-4x+5y-6
分式除法(2y-x)÷x²-4xy+4y²/x+3xy要过程
x^2y+4xy+4y
(-3x^y+2xy)-( )=4x^+xy
-(x的平方y+3xy-4)+3(x的平方y-xy+2),要过程.
数学题 化简,要过程第一题2xy-{5x-3[xy-三分之一x(y+1)]-4xy}第二题二分之一x-(2x-三分之二y
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-
已知3x^2+xy-2y^2=0,求{(x+y)/(x-y)+4xy/(y^2-x^2)}/{(x+3y)*(x-y)}
(x^-4y^)/(x^+2xy+y^)/(x+2y)/(2x^+2xy)
x^3y(-4y)^2+(-7xy)^2*(-xy)-5xy^3*(-3x)^2
已知x-y=4xy,则2x+3xy-2yx-2xy-y
计算(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-x^y^7+y^8)(x^2+xy+y^2)