(x+y-3)+(x-4)i=0
{(x,y)I x+y-3=0且x-y-1=0}
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
x²+y²-4x+6y+13=0,求(3x+y)²-3(3x+y)(x+y)-(x-3y)
求适合下列条件的实数x和y的值:1、(3x+2y)+(5x-y)i=17-2i;2、(3x-4y)+(2y+3)i=0
已知(x+y-3)+(y-4)i=0,其中x,y∈R,i是虚数单位,则x=( )
(2/3x-2/x+y(x+y/3x-x-y))÷x-y/x,其中5x+3y=0
先化简,再求值:【(X+2Y)(X-2Y)-(X+4Y)平方]除4Y,其中X=-2,Y=-3
设2x−yx+y=3,其中x,y≠0,则(2x−3y)3−(3x−2y)3(4x+2y)3−(x−7y)3=( )
若1.2X=4分之3Y,X+Y=2.6 那么X=( )Y=( )
(x-4y)分之(3x)+(4y-x)分之(x+y)-(x-4y)分之(7y)
(X-3Y)(X+3Y)-(X+2Y)(X-4Y)-(2X-Y)2的平方
1.((y+2x)(-2x+y)+4(x+2y)^2)/3y 2.(2(x-y)^3-8(x-y)^2(x+y)+6y(