若函数f(x)=xcos(2x-π/4)-1/2sin(2x-π/4)(0
求函数f(x)=(sin^4x+cos^4x+sin^2xcos^2x)/2
已知函数f(x)=sin^2ωx+√3cosωxcos(π/2-ωx)(ω>0)
已知函数f(x)=2sinωxcosωx(ω>0,x∈R)1.求f(x)的值域2.若f(x)的最小正周期为4π,求ω的值
数学题目已知函数f(x)=+2sinωxcosωx+2f(a)=2/3求sin(5/6π-4a)
求函数f(x)=sin^4x+cos^4x+sin^2xcos^2x/2-2sinxcosx-1/2sinxcosx+1
已知函数f(x)=23sinωxcosωx−2cos2ωx+1(x∈R,ω>0)的周期为π.
已知函数f(x)=a(cos^2 x+sin xcos x)+b.
求函数f(x)=(sin^4x+cos^4x+sin^2xcos^2x)/(2-sin2x)的最小正周期、最大值和最小值
sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos
求函数f(x)=(sin⁴x+cos⁴x+sin²xcos²x)/(2-si
求函数f(x)=(sinx+cos^4x+sin^2xcos^2x)/2-2sinxcosx-1/2sinxcosx+1
求函数y=2sin xcos x+2sin x+2cos x+4的值域