计算:6a(2a3+3a2+4a)\12a2
a3-2a2-4a+3因式分解
1.计算阶行列式1+a1 a2 a3 .ana1 1+a2 a3 .ana1 a2 1+a3.an....a1 a2 a
设a1,a2,a3均为3维列向量,A=(a1,a2,a3).B=(a1+a2+a3,a1+2a2+4a3,a1+3a2+
(4a2-3a+1)-3(-a3+2a2).
已知2a2-3a-5=0,求4a4-12a3+9a2-10的值.
记集合A={1,2,3,4,5,6},M={m|m=a1/10+a2/100+a3/1000,a1,a2,a3∈A},将
设a1,a2,a3均为3维列向量,矩阵A=(a1,a2,a3)并且|A|=1,B=(a1+a2+a3,a1+2a2+4a
设A为3阶方阵.且|A|=3,将A按列分块为(A1,A2,A3),计算|A3,-2A2,3A1|与|A2,3A3-2A1
设A=(a1,a2,a3,a4,a5),a1,a3,a5线性无关,a2=3a1-a3-a5,a4=2a1+a3+6a5,
(a2-1)/(a2+2a+1)除以(a2-a)/(a+1) (a-2/(a+3)除以(a2-4)/(a2+6a+9)
设矩阵A=[a1.a2.a3.a4],其中a2.a3.a4线性无关,a1=2a3-3a4.向量b=a1+2a2+3a3+
设向量组a1,a2,a3线性无关,证明:向量组B1=a1+2a2+a3,B2=a1+a2+a3,B3=a1+3a2+4a