神马作文网化简 tan(x/2 + π/4)-tan(π/4 - x/2)
来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/13 22:30:41
化简 tan(x/2 + π/4)-tan(π/4 - x/2)
tan(x/2 + π/4)-tan(π/4 - x/2)
=tan(x/2+π/4)-cot[π/2-(π/4-x/2)]
=tan(x/2+π/4)-cot(x/2+π/4)
=sin(x/2+π/4)/cos(x/2+π/4)-cos(x/2+π/4)/sin(x/2+π/4)
={[sin(x/2+π/4)]^2-[cos(x/2+π/4)]^2}/[sin(x/2+π/4)cos(x/2+π/4)]
=-cos(x+π/2)/[sin(x+π/2)/2]
=-2cot(x+π/2)
=tan(x/2+π/4)-cot[π/2-(π/4-x/2)]
=tan(x/2+π/4)-cot(x/2+π/4)
=sin(x/2+π/4)/cos(x/2+π/4)-cos(x/2+π/4)/sin(x/2+π/4)
={[sin(x/2+π/4)]^2-[cos(x/2+π/4)]^2}/[sin(x/2+π/4)cos(x/2+π/4)]
=-cos(x+π/2)/[sin(x+π/2)/2]
=-2cot(x+π/2)
1)tan(x/2+π/4)+tan(x/2-π/4)=2tanx
tan（X/2+π/4)+tan（x/2-π/4）=2tanx?
求证:tan（x/2+π/4）+tan(x/2-π/4)＝2tanx
tan（ x/2+π/4）+tan（x/2-π/4 ）=2tanx
tan(x/2+ π4)+tan(x/2- π/4)=2tanx
∫ ( tan^2 x + tan^4 x )dx
求不定积分∫(tan^2x+tan^4x)dx
证明sec x+tanx=tan(π/4 +x/2)
2tan^2(x/2)+2=4tan(
函数y=tan(π/2-x)(-π/4
y=3tan(2x-π/4）
证明tanx+1/cosx=tan(x/2+π/4)