[(x2+y2)÷y-2y]÷(1÷y-1÷x)1÷(x2-y2)-(x-y)÷y怎么做?
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[(x2+y2)÷y-2y]÷(1÷y-1÷x)1÷(x2-y2)-(x-y)÷y怎么做?
[(x2+y2)÷y-2y]÷(1÷y-1÷x)
= [(x2+y2)* 1/y-2y] ÷(1/y -1/x)
= [(x^2-y^2) / y ] ÷ [(x-y) /xy ]
= ( x^2-y^2) / y * xy / (x-y)
= (x+y) * x
= x^2+xy
再问: 拜托,你没有回答完整。是[(x2+y2)÷y-2y]÷(1÷y-1÷x)1÷(x2-y2)-(x-y)÷y
再答: 是的,开始看着象2道题就分开了,算完第一道给忘了,马上补上 1÷(x2-y2)-(x-y)÷y =1*1/(x^2-y^2) - (x-y)/y = [y - (x-y)(x^2-y^2)] / y(x^2-y^2) = (y -x^3 +x^2y +xy^2 -y^3) / y(x^2-y^2) 试了下没法因式分解化简了,题目无误吧?
= [(x2+y2)* 1/y-2y] ÷(1/y -1/x)
= [(x^2-y^2) / y ] ÷ [(x-y) /xy ]
= ( x^2-y^2) / y * xy / (x-y)
= (x+y) * x
= x^2+xy
再问: 拜托,你没有回答完整。是[(x2+y2)÷y-2y]÷(1÷y-1÷x)1÷(x2-y2)-(x-y)÷y
再答: 是的,开始看着象2道题就分开了,算完第一道给忘了,马上补上 1÷(x2-y2)-(x-y)÷y =1*1/(x^2-y^2) - (x-y)/y = [y - (x-y)(x^2-y^2)] / y(x^2-y^2) = (y -x^3 +x^2y +xy^2 -y^3) / y(x^2-y^2) 试了下没法因式分解化简了,题目无误吧?
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